1.

How fast is an electron moving if it has a wavelength equal to the distance it travels in one second?

Answer»

`SQRT((m)/(h))`
`sqrt((h)/(m))`
`sqrt((h)/(p))`
`sqrt((h)/(2(KE)))`

Solution :Distance travelled in 1 sec = velocity (V)
Given `LAMDA = v`. HENCE, `lamda = (h)/(mv)` becomes `v = (h)/(mv)`
or `v^(2) = (h)/(m) or v = sqrt((h)/(m))`


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