How is propyne prepared from an alkyene dihalide ?

1.	How is propyne prepared from an alkyene dihalide ?
Answer» Solution :`CH_(3)-CH_(2)- underset(CI) underset(\|)overset( CI) overset( \|) (C ) -Hoverset( ALC. KOH) (to)CH_(3) - CH = underset( CI )underset(\|) (C ) - H + HCI` (1,1,- dichloroprpane )(1- Chloroprop -1- ene ) `CH_(3)- C = CH` (propyne )

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