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How is the resultant of two like parallel forces obtained, using the theorem of moments ? |
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Answer» <P> Solution :Taking moments of forces P and Q about 'c' , we get `Pbar(AC)=Qbar(BC)`MOMENT of P about O=`Pbar(AO)` Moment of Q about O=`Qbar(BO)` Algebraic SUM of moments of forces about O=`Pvar(AO)+Qbar(BC)` `=P(AC+OC)+Q(OC-BC)` `=Pbar(AC)+Pbar(OC)+Qbar(OC)+Qbar(BC)` `=(P+Q)bar(OC)` `:.Pbar(AO)+Qbar(BO)=Rbar(OC)` 
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