How long a current of `3A` has to be passed through a solution of silver nitrate to coat a metal surface of `80cm^(2)` with a `0.005-mm-` thick layer ? The density of silver is `10.5g cm^(-3)`.

How long a current of `3A` has to be passed through a solution of silv

1.	How long a current of `3A` has to be passed through a solution of silver nitrate to coat a metal surface of `80cm^(2)` with a `0.005-mm-` thick layer ? The density of silver is `10.5g cm^(-3)`.
Answer» Correct Answer - `125.09s` Volume of the surface `(V)=` Area `xx` Thickness Given, Area `=80cm^(2),` thickness `=0.005mm=0.00005cm` Mass of `Ag(W)=Vxx` Density `=0.04xx10.5=0.42g` `Ag^(o+)+e^(-) rarr Ag` `:. W_(Ag)=(Zit)/(96500)` `0.42=(108xx3xxt)/(96500)` `:. t=(0.42xx96500)/(108xx3)=(40530)?(324)=125.90s`

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How long a current of `3A` has to be passed through a solution of silver nitrate to coat a metal surface of `80cm^(2)` with a `0.005-mm-` thick layer ? The density of silver is `10.5g cm^(-3)`.

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