How long has a current of 3 ampere to be applied through a solution of silver nitrate to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer ? Density of silver is `10.5 g//cm^(3)`.

How long has a current of 3 ampere to be applied through a solution of

1.	How long has a current of 3 ampere to be applied through a solution of silver nitrate to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer ? Density of silver is `10.5 g//cm^(3)`.
Answer» Mass of silver to be deposited = volume `xx` density = area `xx` thickness `xx` density Given : Area `=80 cm^(2)`, thickness =0.0005 cm and density `=10.5 g//cm^(3)` Mass of silver to be deposited `=80xx0.0005xx10.5` `=0.42 g` Applying to silver `E=Zxx96500` `Z=108/96500 g` Let the current be passed for t seconds. We know that, `W=ZxxIxxt` So, `0.42=108/96500xx3xxt` or `t=(0.42xx96500)/(108xx3)=125.09` second

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How long has a current of 3 ampere to be applied through a solution of silver nitrate to coat a metal surface of `80 cm^(2)` with 0.005 mm thick layer ? Density of silver is `10.5 g//cm^(3)`.

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