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| 1. |
How long will it take an electric current of 0.15 A to deposit all the copper from 500ml of 0.05M copper sulphate solution. |
| Answer» MARK me as brainliestExplanation:ZN 2+ +2e − ⟶Zn1 mole is deposited by 2×96500=193000CThe charge supplied = 0.965×10×60=579C∴ Number of moles deposited = 193000579 =0.003 MOLESIN 500ml, number of moles = 1000500 ×0.2=0.1 moles∴ Moles remaining in the 500ml solution = 0.1−0.003=0.097 moles∴ MOLARITY = 5001000 ×0.097=0.194M | |