How m any number of proton, electron and neutron n in .^(55)Mn^(+2) re

1.	How m any number of proton, electron and neutron n in .^(55)Mn^(+2) respectively ?
Answer» 25,27,30 25,25,30 25,23,30 25,27,26 Solution :`._(25)^(55)Mn^(2+)` No. of PROTONS = 25 No. of ELECTRONS = 25 - 2 = 23 No. of neutrons = 25 - 25 = 30

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