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How many `176 Omega` resistors (in parallel) are required to carry 5 A in 220 V line ? |
Answer» Here, `I = 5 A, V = 220 V`. Resistance required in the circuit, `R = (V)/(I) = (220 V)/(5 A) = 44 Omega` Resistance of each resistor, `r = 176 Omega` If `n` resistors, each of resistance `r`, are connected in parallel to get the required resistance `R`, then `R = ( r)/(n)` or `44 Omega = (176 Omega)/(n)` or `n = (176 Omega)/(44 Omega) = 4`. |
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