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How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming that (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed? |
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Answer» (i) When repetition of digits is allowed: No. of ways of choosing firsy digits = 5 No. of ways of choosing second digit = 5 No. of ways of choosing third digit = 5 Therefore, total possible numbers `= 5 xx 5 xx 5 = 125` (ii) When repetition of digits is not allowed: No. of ways of choosing first digit = 5 No. of ways of choosing second digit = 4 No. of ways of choosing thrid digit = 3 Total possible numbers `= 5 xx 4 xx 3 = 60`. |
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