How many 6 - digit numbers can be formed by using the digits 4, 5, 0,

1.	How many 6 - digit numbers can be formed by using the digits 4, 5, 0, 3, 4, 5?
Answer» To find: number of 6 digit 0 cannot be in the first place because that would make a 5 - digit number Total number of 6 - digit numbers = Total number of number possible - Number of numbers with 0 at the first place Total number of numbers possible = \(\frac{6!}{2!2!}\) = 180 Number of numbers with 0 at first place = \(\frac{5!}{2!2!}\) = 30 ⇒ Number of 6 - digit numbers = 180 - 30 = 150 150 six - digit numbers are possible

How many 6 - digit numbers can be formed by using the digits 4, 5, 0, 3, 4, 5?

Answer»

To find: number of 6 digit

0 cannot be in the first place because that would make a 5 - digit number

Total number of 6 - digit numbers = Total number of number possible - Number of numbers with 0 at the first place

Total number of numbers possible = \(\frac{6!}{2!2!}\) = 180

Number of numbers with 0 at first place = \(\frac{5!}{2!2!}\) = 30

⇒ Number of 6 - digit numbers = 180 - 30 = 150

150 six - digit numbers are possible