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How Many 7 Digit Numbers Can Be Formed Using The Digits 1, 2, 0, 2, 4, 2, 4?

Answer»

There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 TIMES, 4 occurs 2 times.

Number of 7 digit NUMBERS = 7!3!×2! = 420 

But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers.

The number of such numbers beginning with '0'. 

=6!3!×2! = 60

Hence the required number of 7 digits numbers = 420 - 60 = 360.

There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 times, 4 occurs 2 times.

Number of 7 digit numbers = 7!3!×2! = 420 

But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers.

The number of such numbers beginning with '0'. 

=6!3!×2! = 60

Hence the required number of 7 digits numbers = 420 - 60 = 360.



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