How many amperes would be needed to produce 60.0 g of magnesium during the electrolysis of molten `MgCl_(2)` in 2 hours ?

How many amperes would be needed to produce 60.0 g of magnesium during

1.	How many amperes would be needed to produce 60.0 g of magnesium during the electrolysis of molten `MgCl_(2)` in 2 hours ?
Answer» Correct Answer - 67 A `Mg^(2+)(aq)+underset(2F)underset(1mol)2e^(-) to underset(24" g.")underset(1" mol")(Mg(s))` 24.0 g of Mg are produced by passing charge `=2xx96500" C"` 60.0 g of Mg are produced by passing charge `=((60g))/((24.0g))xx(2xx96500C)=482500" C"` `l=(Q)/(t)=((482500" C"))/((2xx60xx60s))=67.0" amp"`

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How many amperes would be needed to produce 60.0 g of magnesium during the electrolysis of molten `MgCl_(2)` in 2 hours ?

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