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How many atoms of fluorine are present in 1.9 xx 10^(-6) gram of fluorine ? The atomic mass of fluroine is 19 amu. |
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Answer» 19.0 gram of fluorine have atoms `= 6.022 xx 10^(23)` `1.9 xx 10^(-6)` gram of fluorine have atoms `= (6.022xx10^(23)xx(1.9xx10^(-6)g))/((19.0g))=6.022xx10^(16)` atoms. |
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