1.

How many atoms of silver are present in silver wire weighing 5.4g?

Answer»
5.4/108 × NA = number of atoms of silver

Molecular weight of silver atom  = 108 g/m

Weight of silver wire = 5.4 g

\(\therefore\) Number of moles of silver atoms = \(\frac{5.4g}{108g/mol}\) = 0.05 mol

\(\because\) We know that

one mole atom contain = 6.023 x 1023 atoms.

\(\therefore\) 0.05 mol silver atom contain = 6.023 x 1023 x 0.05 atom

 = 0.30115 x 1023 silver atom

 = 3.0 x 1022 silver atom.

Hence, 5.4 g silver wire contain 3.0 x 1022 silver atoms.



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