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How many atoms of silver are present in silver wire weighing 5.4g? |
Answer» Molecular weight of silver atom = 108 g/m Weight of silver wire = 5.4 g \(\therefore\) Number of moles of silver atoms = \(\frac{5.4g}{108g/mol}\) = 0.05 mol \(\because\) We know that one mole atom contain = 6.023 x 1023 atoms. \(\therefore\) 0.05 mol silver atom contain = 6.023 x 1023 x 0.05 atom = 0.30115 x 1023 silver atom = 3.0 x 1022 silver atom. Hence, 5.4 g silver wire contain 3.0 x 1022 silver atoms. |
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