1.

How many calories are requiredto heat 40 gram of argonfrom 40 to100^(@)C at constant volume ?( R= 2 cal // molK)

Answer»

120
2400
1200
180

Solution : For a monoatomic gas like argon, `C_(v) = 3cal mol^(-1), C_(p) = 5 cal mol^(-1)`. Molar HEAT capacity is the heat required to raise the temperature of 1 MOLE of the gas by `1^(@)C `. 40 g of argon `=` 1 mole. Hence,heat required to raiseto raise the temperature from `40^(@)` to `100^(@)C` at constant volume `= 3 xx ( 100 - 40) = 180 cal`


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