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How many change in electron and electric charge in balance half reduction reaction for following redox reaction on left hand side ? Cr^(3+)+ClO_(3)^(-)toClO_(2)^(-)+Cr_(2)O_(7)^(2-) |
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Answer» `6,-3` `UNDERSET((+5))(ClO_(3)^(-))tounderset((+3))(ClO_(2)^(-))` `ClO_(3)^(-)+2e^(-)underset(2H^(+))toClO_(2)^(-)+H_(2)O` Number of `e^(-)=2xx3=6` CHARGES = 3 Balance above reaction multiply by 3 for completion. |
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