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How many consecutive natural numbers from 1 should be added to get 465? |
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Answer» Sum of first n natural numbers = \(\frac{n(n+1)}{2}=465\) n2 + n = 930 \(n^2+n+\frac{1}{4}=930+\frac{1}{4}\) \((n+\frac{1}{2}){^2}=\frac{3721}{4},n+\frac{1}{2}=\frac{61}{2}\) n = 30 The sum of first 30 natural numbers = 465 |
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