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How many copper will be deposited at cathode of an electrolytic cell containing `Cu^(2+)` ions by passing 2 ampere of current for 60 minutes.

Answer» Correct Answer - 2.37 g
`Cu^(2+)(aq)+underset(2F)underset(2" mol")(2e^(-)) to underset(63.5 g)underset(1" mol")(Cu(s))`
Quantity of charge (Q) passed `=(2"amp".)xx(60xx60s)=7200"C"`
`2xx96500C` of charge deposit `Cu=((63.5 g))/((2xx96500C))xx(7200C)=2.37 g`.


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