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How many coulombs are required for the oxidation of 1 mol of `H_(2)O_(2)` ?A. `93000C `B. `1.93 xx 10^(5) C`C. `9.65 xx 10^(4) C`D. `19.3 xx 10^(3) C`. |
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Answer» Correct Answer - B `H_(2)O_(2) to H_(2)O + (1)/(2) O_(2)` Oxidation of 1 mole of `H_(2)O_(2)` means both `O^(-)` ions should change to `O_(2)` , i.e,`2 O^(-) to O_(2) + 2e^(-)` Thus , 1 mole of `H_(2)O_(2)` requires = 2 F = `2 xx 96500 C = 1.93 xx 10^(5)` C (Remember that the given reaction is a disproportionation reaction `2H_(2)O_(2) to 2H_(2)O + O_(2)` in which 1 mole is reduced) , `H_(2)O_(2) to H_(2)O + (O)` and 1 mole is oxidized , `H_(2)O_(2) + (O) to H_(2)O + O_(2)` |
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