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How many coulombs of electricity are required for complete oxidation of 90 g of `H_(2)O`? |
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Answer» 90g of `H_(2)O=(90)/(18)" moles"=5"moles"` 1 mole of `H_(2)O` requires electricity=2F `therefore`5moles of `H_(2)O` will require electricity`=5xx2F=10F=10xx96500=965000C` (ii) 1000 mL of 1 M `KMnO_(4)` solution contain `KMnO_(4)=1` mol `therefore`100 mL of 0.1 M `KMnO_(4)` solution contain `KMnO_(4)=(1)/(1000)xx100xx0*1mol=0*01`mol 1 mole of `KMnO_(4)` requires electricity=5F `therefore0*01" mol of "KMnO_(4)` will require electricity=`0*01xx5F=0*05F=0*05xx96500C=4825C` |
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