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How many electrons in sulphur (Z = 16) can have `n + l = 3` ?

Answer» Electronic configuration of `._(16)S = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(4)`
For `1s^(2), n + l = 1 + 0 = 1`. For `2s^(2), n + l = 2 + 0 =2`. For `2p^(6), n + l = 2 + 1 = 3`
For `3s^(2), n + l = 3 + 0 = 3` For `3p^(4), n + l = 3 + 1 = 4`
Thus, `n + l = 3 " for " 2p^(6) and 3s^(2)` electrons, i.e., for 8 electrons


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