1.

How many electrons must be removed from a piece of metal to give it a positive charge of \( 1.0 \times 10^{-7} C \).

Answer»
q=+or- ne 
1.0×10^-7 =n×1.6×10^-10
n=1.0×10^-7/1.6×10^-19
=1.0×10^-7+19/1.6
=1.0×10^12/1.6 
=10×10^12/16
=0.625×10^12
=6.25×10^11.


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