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How many electrons must be removed from a piece of metal to give it a positive charge of \( 1.0 \times 10^{-7} C \). |
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Answer» q=+or- ne 1.0×10^-7 =n×1.6×10^-10 n=1.0×10^-7/1.6×10^-19 =1.0×10^-7+19/1.6 =1.0×10^12/1.6 =10×10^12/16 =0.625×10^12 =6.25×10^11.
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