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How many electrons per sec pass through a cross-section of a copper wire carrying `10^(-15)` ampere? |
Answer» Current strength `(i) = ("Total charge")/("Time (in sec.)")=(C)/(s)` Also Total charge = Number of electron `xx` Change on one electron `:. i = ("Number of electron" xx "Charge on one electron")/("Time (in sec.)")` `:.` No. of electron passed in `1` sec. `= (i)/("Charge on 1 electron") = (10^(-15))/(1.6 xx 10^(-19)) = 6250` |
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