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How many electrons required to received by oxidising agent KMnO_(4) to converted into MnO_(4)^(-2),MnO_(2),Mn_(2)O_(3)andMn^(+2) ? |
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Answer» 4, 3, 1, 5 `KMnO_(4)overset(+3E^(-))toMnO_(2)" "[Mn(+4)]` `KMnO_(4)overset(+4e^(-))to1/2Mn_(2)O_(3)" "[Mn(+3)]` `KMnO_(4)overset(+5e^(-))toMn^(+2)" "[Mn(+2)]` |
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