1.

How many electrons required to received by oxidising agent KMnO_(4) to converted into MnO_(4)^(-2),MnO_(2),Mn_(2)O_(3)andMn^(+2) ?

Answer»

4, 3, 1, 5
1, 5, 3, 7
1, 3, 4, 5
3, 5, 7, 1

Solution :`KMnO_(4)OVERSET(+1E^(-))to(MnO_(4))^(-2)" "[Mn(+6)]`
`KMnO_(4)overset(+3E^(-))toMnO_(2)" "[Mn(+4)]`
`KMnO_(4)overset(+4e^(-))to1/2Mn_(2)O_(3)" "[Mn(+3)]`
`KMnO_(4)overset(+5e^(-))toMn^(+2)" "[Mn(+2)]`


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