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How many equivalents are there per mole of `H_(2)S` in its oxidation to `SO_(2)`? |
Answer» `H_(2)S rarrSO_(2)` or `S^(2-) rarrS^(4+) + 6e` `N_(H_(2)S) = M_(H_(2)S) xx 6` `because ("Moles")/("Equivalent") = (N)/(M) = 6` Thus one mole of `H_(2)S` has `6` equivalent in it. |
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