1.

How many g of dibasic acid (mol. weight 200)should be present in 100 ml. of the aqueoussolution to give strength of 0.1 N?(1) 10 g(3) 1g(2) 2g(4) 20 g

Answer»

Equivalent wt. of dibasic acid = mol. wt/2

= 200/2 = 100

Strength = 0.1 N,

m = ? ,

V = 100 mL then,

m = EVN/1000 = (100 x 100 x 0.1)/1000

= 1gm.



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