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InterviewSolution
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How many gm of bromine will react with 21 gm `C_3H_6`A. 80B. 160C. 240D. 320 |
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Answer» Correct Answer - A `undersetundersetunderset"42 gms""1 mole""Propene"(CH_3-CH)=CH_2+undersetunderset"160 gms""1 mole"(Br_2)to CH_3-underset"1,2-Dibromo propane"(undersetunderset(Br)(|)CH_2-undersetunderset(Br)(|)CH_2)` `because` 24 gms of propene reacts with 160 gms of bromine `because` 21 gms of propene `160/42xx21=80` gms |
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