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How many gram atoms are present in 4000 amu of calcium ? |
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Answer» Solution :4000 amu of `Ca =40xx10^(2)xx1.66xx10^(-24)g` One gram atom of Ca=40g NUMBER of gram atoms of Ca in 4000 amu `=(40xx1.66xx10^(2)xx10^(-24))/40=1.66xx10^(-22)` |
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