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How many grams of anhydrous sodium carbonate can be decomposed using 50mL of seminormal hydrochloric acid? |
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Answer» Solution :Number of milli EQUIVALENT of acid `=50xx0.5=25` Number of milli equivalents of `Na_(2)CO_(3)-25` Number of milli equivalents of `Na_(2)CO_(3)=25` 1 equivalent =1000m.eq = 53g of `Na_(2)CO_(3)` 25m.eq=? Weight of `Na_(2)CO_(3)` DECOMPOSED when treated with the given acid solution `=53xx(25)/(1000)=1.325g` |
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