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How many grams of carbon and oxygen are required to get the same number of atoms as in one gram of Helium? |
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Answer» GAM of Helium = 4 g Number of mole atoms in 4g of Helium = 6.022 x 1023 Number of atoms in 1g of Helium = \(\frac{1}{4}\) x 6.022 x 1023 GAM of Carbon = 12 g ∴ Number of atoms in 12g of Carbon = 6.022 x 1023 ∴ Mass required for \(\frac{1}{4}\) x 6.022 x 1023 Carbon atoms = 3g (12 x \(\frac{1}{4}\)) GAM of Oxygen = 16 g. ∴ Number of atoms in 16 g of Oxygen = 6.022 × 1023 ∴ Mass required for \(\frac{1}{4}\) x 6.022 × 1023 Oxygen atoms = 4g (16 x \(\frac{1}{4}\)) |
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