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How many grams of caustic potash required to completely neutralise `12.6 g HNO_(3)`?A. (a)`22.4 KOH `B. (b)` 1.01 KOH`C. (c )` 6.02 KOH`D. (d)`11.2 KOH ` |
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Answer» Correct Answer - D `HNO_(3)+KOH rarr KNO_(3)+H_(2)O` `12.6/63=0.2 "mole", HNO_(3)-= KOH` `0.2"mole"-= 0.2 "mole"` `0.2xx56=11.2 g`. |
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