How many grams of CaWO_4 would contain the same mass of tungsten that is present in 569 g of FeWO_4? (W = 184)

How many grams of CaWO_4 would contain the same mass of tungsten that

1.	How many grams of CaWO_4 would contain the same mass of tungsten that is present in 569 g of FeWO_4? (W = 184)
Answer» Solution :LET the mass of `CaWO_(4)` be w g. As given mass of W in w g of `CaWO_(4)`= mass of W in 569 g of `FeWO_(4)` Moles of W in `CaWO_(4) xx` at. Wt. of W = moles of W in `FeWO_(4)xx` wt of W. As both `CaWO_(4)` and `FeWO_(4)` CONTAIN 1 atom of W each. `THEREFORE` moles of `CaWO_(4) xx` at wt. of W = moles of `FeWO_(4) xx` at. wt of W `w/288 xx 184 = 569/304 xx 184` w= 539.05 g