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How many grams of concentrated nitric acid solution should be used to prepare `250 mL` of `2.0 M HNO_(3)`? The concentrated acid is `70% HNO_(3)`:A. (a)`90.0` g conc. `HNO_(3)`B. (b)`70.0` g conc. `HNO_(3)`C. (c )`54.0` g conc. `HNO_(3)`D. (d)`45.0` g conc. `HNO_(3)` |
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Answer» Correct Answer - d `1000 mL` has 2 moles `250 mL` has `2/1000xx250=0.5` moles `implies n=W/M implies W=nxxM-0.5xx63 g` As `70 g` of `HNO_(3)` is in `100 g` solution So, `0.5xx63 g` of `HNO_(3)` is in `100/70xx0.5xx63=45 g` [We have assumed `70%` (mass by mass), although it should have been reported.] |
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