How many grams of dibasic acid (molecular mass 200) should be present in 100 mL of the aqueous solution to give 0.1 N solution ?

How many grams of dibasic acid (molecular mass 200) should be present

1.	How many grams of dibasic acid (molecular mass 200) should be present in 100 mL of the aqueous solution to give 0.1 N solution ?
Answer» 1G 2g 10 G 20 g Solution :Molarity of ACID `= 0.1//2 = 0.05 M` Molarity `= (("Mass of acid")/("Molar mass"))/("Volume in litre")` `(0.05 MOLL^(-1))=(W)/(("200 g mol"^(-1))xx("0.1 L"))` `W = (0.05 mol L^(-1))xx("200 g mol"^(-1))xx(0.1 L) =-1g`.