1.

How many grams of do basic acid (mol wt = 200) should be present in 100 ml of the aqueous solution to give 1 Normal?​

Answer»

1 gExplanation:MOLARITY of DIBASIC acidM= 200ω × 1001000 N=M×2→ dibasic acid101 = 200ω × 1001000 ×2ω= 10001000 ω=1gmSo , CORRECT ANSWER is 1G



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