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How many grams of `H_(2)SO_(4)` are present in `500ml` of `0.2M H_(2)SO_(4)` solution ? . |
Answer» `M = ("moles")/("vol") rArr` moles of `H_(2)SO_(4) = M xx V = 0.2 xx (500)/(1000) L = 0.1` Mass of `H_(2)SO_(4) = 0.1 xx 98 = 9.8g` . |
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