1.

How many grams of `H_(2)SO_(4)` is/are to be dissolved to prepare 200 mL aqueous solution having concentration of `[H_(3)O^(+)]` ions is 1 M at `25^(@)C` temperature?A. 19.6 gB. 0.98 gC. 4.9 gD. 9.8 g

Answer» Correct Answer - d
Molarity, `M = (w_(2)xx1000)/(M_(2)xxV("in" mL))`
where, `w_(2)` is the mass of `H_(2)SO_(4)` in g and `M_(2)` is the molar mass of `H_(2)SO_(4)`.
`w_(2) = (1xx98xx200)/(1000) = 19.6 g`
`H_(2)SO_(4) + 2H_(2)O hArr 2H_(3)O^(+) + SO_(4)^(2-)`
But according to equation, 1 mole of `H_(2)SO_(4)` gives 2 moles of `[H_(3)O^(+)]` ions. Thus, the amount of `H_(2)SO_(4)` to prepare 200 mL solution having 1 M concentration of `H_(3)O^(+)` ions is 19.6/2 = 9.8 g.


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