1.

How many grams of NaOH can neutralise 100 ml ofH_2SO_4solution with P^(H)solution with P^(H)value 3.301?

Answer»

2mg
3 mg
4 mg
0.4 mg

Solution :` pH = 3.3 rArr [H^(+) ] = 5XX 10 ^(-4) `
` therefore ` moles of acid ` = 0.1 xx 5 xx 10 ^(-4)= 5 xx 10 ^(-5) `
to NEUTRALIZE , MOLESOF NaOH`= 5 xx 10 ^(-5) `
` therefore ` weight` = 40 xx 5 xx 10 ^(-5)= 2 xx 10 ^(-3)= 2 mg `


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