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How many grams of NaOH can neutralise 100 ml ofH_2SO_4solution with P^(H)solution with P^(H)value 3.301? |
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Answer» 2mg ` therefore ` moles of acid ` = 0.1 xx 5 xx 10 ^(-4)= 5 xx 10 ^(-5) ` to NEUTRALIZE , MOLESOF NaOH`= 5 xx 10 ^(-5) ` ` therefore ` weight` = 40 xx 5 xx 10 ^(-5)= 2 xx 10 ^(-3)= 2 mg ` |
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