How many grams of nitric acid can be prepared from 50.0 g of KNO_3 of

1.	How many grams of nitric acid can be prepared from 50.0 g of KNO_3 of 80% purity ?
Answer» SOLUTION :The coresponding equation is: `underset(2 xx 101.11 g)(2KNO_(3)) + H_(2)SO_(4) to underset(2 xx 63.018 g)(2HNO_(3)) + K_(2)SO_(4)` Since, the given sample of `KNO_(3)` in 50.0 g of it `(50.0 xx 80)/100= 40.0 g` `THEREFORE 2 xx 101.11 g` of `KNO_(3)` GIVE `HNO_(3) = 2 xx 63.018 g` `therefore 40.0 g` of `KNO_(3)` will give `HNO_(3)` `=(2 xx 63.018)/(2 xx 101.11) xx 40.0 = 24.9 g` Hence, the given sample of `KNO_(3)` can give 24.9 g of `HNO_(3)`

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