How many grams of oxygen gas is essentially required for complete comb

1.	How many grams of oxygen gas is essentially required for complete combustion of 3 moles of butane gas? (1) 624 g (2) 312 g (3) 128 g (4) 64 g
Answer» (1) 624 g 2 C₄ H₁₀+ 13O₂ → 8 CO₂ + 10 H₂ O 2 moles required 13 mole O₂ 1 mole required 13/2 mole O₂ 3 mole required 13/2 x 3 = 39/2 = 19.5 mole Wt of O₂ required = 19.5 x 32 = 624 g

How many grams of oxygen gas is essentially required for complete combustion of 3 moles of butane gas? (1) 624 g (2) 312 g (3) 128 g (4) 64 g

Answer»

(1) 624 g

2 C₄ H₁₀+ 13O₂ → 8 CO₂ + 10 H₂ O

2 moles required 13 mole O₂

1 mole required 13/2 mole O₂

3 mole required 13/2 x 3 = 39/2 = 19.5 mole

Wt of O₂ required = 19.5 x 32 = 624 g

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How many grams of oxygen gas is essentially required for complete combustion of 3 moles of butane gas? (1) 624 g (2) 312 g (3) 128 g (4) 64 g

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