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How many grams of oxygen `(O_(2))` gas reacts completely with `1.0g` of calcium?A. `0.6 g`B. `1.6 g`C. `4.0 g`D. `0.4 g` |
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Answer» Correct Answer - D `Ca + O_(2) rarr CaO` According to formula, Moles of `C` = Moles of `O` `("Mass"_(Ca))/("Molar mass"_(Ca)) = ("Mass"_(O))/("Molar Mass"_(O))` `(1g Ca)/(40g Ca) = (m_(O))/(16g O)` `:. M_(O) = 0.4g` We can use this approach because the enite `Ca` is changed into `CaO`. |
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