1.

How many hours does it take to reduce 3 moles of Fe3+ to Fe2+ with 2.0 A current intensity?

Answer»

Fe3+ + e → Fe2+

3 mole Fe3+ will require 3-mole electrons.

Required charge = 3 × 96500 coulomb = 289500 coulomb

Charge = Current × Time

Time \(\frac{Charge}{Current}\) = \(\frac{289500}{2}\) = 1.44750 x 105 sec. = 40 hrs



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