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How many ions are produced from the complex `Co(NH_3)_6Cl_2` in solution? (i). `6` (ii). `4` (iii). `3` (iv). `2` |
Answer» Coordination number of cabot =6 Hence, the complex is `[Co(NH_(3))_(6)]Cl_(2)` it ionizes in the solution as follows: `[Co(NH_(3))_(6)]Cl_(2)overset(+aq)rarr[Co(NH_(3))_(6)]^(2+)+2Cl^(-)` Thus, three ions are produced Hence the correct option is (III) |
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