1.

How many isomers of C_(5)H_(11)OH will be primary alcohols?

Answer»

5
2
4
3

Solution :(i) `H_(3)C-CH_(2)-CH_(2)-CH_(2)-CH_(2)-OH`,
(ii) `CH_(3)-CH_(2)-UNDERSET(CH_(2))underset(|)(CH)-CH_(2)-OH`,
(iii) `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-OH`
(iv) `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-OH`


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