How many joules of energy must be absorbed to convert Li to `Li^(+)` , all the atoms present in `1.00` mg of gaseous Li ? `lE_(1)` of Li is `520.3 kJ mol^(-1)(Li=7)` .A. `0.00743 kJ`B. `0.520 kJ`C. `520 kJ`D. `0.0743 kJ`

How many joules of energy must be absorbed to convert Li to `Li^(+)` ,

1.	How many joules of energy must be absorbed to convert Li to `Li^(+)` , all the atoms present in `1.00` mg of gaseous Li ? `lE_(1)` of Li is `520.3 kJ mol^(-1)(Li=7)` .A. `0.00743 kJ`B. `0.520 kJ`C. `520 kJ`D. `0.0743 kJ`
Answer» `1.00 mg=1xx10^(-3)g=(1x10^(-3))/(7)` mol Li 1 mole of Li is converted by `520.3 kJ`. `therefore(1xx10^(-3))/(7)` mole is converted to `Li^(+)` by `=(520.3xx1xx10^(-3))/(7)kJ=0.0743 kJ`

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How many joules of energy must be absorbed to convert Li to `Li^(+)` , all the atoms present in `1.00` mg of gaseous Li ? `lE_(1)` of Li is `520.3 kJ mol^(-1)(Li=7)` .A. `0.00743 kJ`B. `0.520 kJ`C. `520 kJ`D. `0.0743 kJ`

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