InterviewSolution
Saved Bookmarks
| 1. |
The electron affinity values (in `kJ mol^(-1))` of three halogens, `x,y`, and `z`are, respectively, `-349, -333`, and `-325`. Then `x, y`, and `x`, are respectively,A. `F_(2), Cl_(2)` and `Br_(2)`B. `Cl_(2), F_(2)` and `Br_(2)`C. `Cl_(2), Br_(2)` and `F_(2)`D. `Br_(2), Cl_(2)` and `F_(2)` |
|
Answer» The electron affinity for halogens, `F=332.6 ~~ 333 rArr Y` `Cl =-348.5 ~~ -349 rArr X` `Br = - 324.7 ~~ 325 rArr Z` X has the highest value of electron affinity. Therefore, the correct order of electron affinity is `Cl_(2)gt F_(2) gt Br_(2)` |
|