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How many lamps each of `50W`and `100W`can be connected in parallel across a `120V` battery of internal resistance `10 Omega` so the each glows to full power ?A. 2B. 4C. 6D. 8

Answer» Correct Answer - b
Resistance of each lamp `R = V^(2)//P = (100)^(2)//50`
`= 200 Omega` , current through each lamp `= P//V= 50//100 = 1//2A`
If there n lamps in parallel to a battery of `120V` current each lamp glown to fall power then total current in n cell `= n xx 1//2 A ,`
Total resistance of circuit `= 10 + 200//n`
As, current `= ("emf")/("total resistance")`
So `(n)/(2) = (120)/(10+200//n)`
On solving we get , `n = 4`


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