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How many litre of Oxygen required for complete conbustion of `6.0g` ethane at `NTP` ? |
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Answer» `2C_(2)H_(6)+7O_(2)rarr4CO_(2)+6H_(2)O` `60g` ethane required `O_(2)` (at `NTP`) `=7xx22.4` litre `1g` ethane required `O_(2)` (at `NTP`) `=(7xx22.4)/(2xx30)litre` `6g` ethane required `O_(2)` (at `NTP`) `=(7xx22.4)/(2xx30)xx6=15.68` litre |
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