How many litres of Oxygen at stp will be required for complete combust

1.	How many litres of Oxygen at stp will be required for complete combustion of 4.4g of propane.
Answer» Explanation: the BALANCED chemical equation representing the reaction is C3H8 + 5O2 ---> 3CO2 + 4H2O 1 MOLE (44g) propane =5 × 22.4 L O2 at *STP* • 2.2 g *propane* = 5 × 22.4 × 2.2 /44 *litre* O2 *answer* = 5.6 *litre* O2 at *STP*

How many litres of Oxygen at stp will be required for complete combustion of 4.4g of propane.

Answer»

Explanation:

the BALANCED chemical equation representing the reaction is

C3H8 + 5O2 ---> 3CO2 + 4H2O

1 MOLE (44g) propane

=5 × 22.4 L O2 at STP

• 2.2 g propane = 5 × 22.4 × 2.2 /44 litre O2

answer = 5.6 litre O2 at STP