How many milli-gram of iron (Fe^(2+))are equal to 1mL of 0.1055N K_(2) Cr_(2)O_7equivalent ?

How many milli-gram of iron (Fe^(2+))are equal to 1mL of 0.1055N K_(2)

1.	How many milli-gram of iron (Fe^(2+))are equal to 1mL of 0.1055N K_(2) Cr_(2)O_7equivalent ?
Answer» 5.9 mg 0.59 mg 59 mg `59 XX 10^(-3) mg` SOLUTION :`w/56 xx100=1xx0.1055` `w = (0.1055xx56)/1000 = 5.9` mg